Optimal. Leaf size=407 \[ \frac {(e x)^{m+1} (A b (a d (m-4 n+1)-b c (m-2 n+1))+a B (b c (m+1)-a d (m-2 n+1)))}{2 a^2 e n^2 (b c-a d)^2 \left (a+b x^n\right )}+\frac {(e x)^{m+1} \, _2F_1\left (1,\frac {m+1}{n};\frac {m+n+1}{n};-\frac {b x^n}{a}\right ) \left (A b \left (a^2 d^2 \left (m^2+m (2-5 n)+6 n^2-5 n+1\right )-2 a b c d \left (m^2+m (2-4 n)+3 n^2-4 n+1\right )+b^2 c^2 \left (m^2+m (2-3 n)+2 n^2-3 n+1\right )\right )+a B \left (-a^2 d^2 \left (m^2+m (2-3 n)+2 n^2-3 n+1\right )+2 a b c d (m+1) (m-2 n+1)-b^2 c^2 (m+1) (m-n+1)\right )\right )}{2 a^3 e (m+1) n^2 (b c-a d)^3}+\frac {d^2 (e x)^{m+1} (B c-A d) \, _2F_1\left (1,\frac {m+1}{n};\frac {m+n+1}{n};-\frac {d x^n}{c}\right )}{c e (m+1) (b c-a d)^3}+\frac {(e x)^{m+1} (A b-a B)}{2 a e n (b c-a d) \left (a+b x^n\right )^2} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 1.25, antiderivative size = 407, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 3, integrand size = 31, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.097, Rules used = {595, 597, 364} \[ \frac {(e x)^{m+1} \, _2F_1\left (1,\frac {m+1}{n};\frac {m+n+1}{n};-\frac {b x^n}{a}\right ) \left (A b \left (a^2 d^2 \left (m^2+m (2-5 n)+6 n^2-5 n+1\right )-2 a b c d \left (m^2+m (2-4 n)+3 n^2-4 n+1\right )+b^2 c^2 \left (m^2+m (2-3 n)+2 n^2-3 n+1\right )\right )+a B \left (-a^2 d^2 \left (m^2+m (2-3 n)+2 n^2-3 n+1\right )+2 a b c d (m+1) (m-2 n+1)-b^2 c^2 (m+1) (m-n+1)\right )\right )}{2 a^3 e (m+1) n^2 (b c-a d)^3}+\frac {(e x)^{m+1} (A b (a d (m-4 n+1)-b c (m-2 n+1))+a B (b c (m+1)-a d (m-2 n+1)))}{2 a^2 e n^2 (b c-a d)^2 \left (a+b x^n\right )}+\frac {d^2 (e x)^{m+1} (B c-A d) \, _2F_1\left (1,\frac {m+1}{n};\frac {m+n+1}{n};-\frac {d x^n}{c}\right )}{c e (m+1) (b c-a d)^3}+\frac {(e x)^{m+1} (A b-a B)}{2 a e n (b c-a d) \left (a+b x^n\right )^2} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 364
Rule 595
Rule 597
Rubi steps
\begin {align*} \int \frac {(e x)^m \left (A+B x^n\right )}{\left (a+b x^n\right )^3 \left (c+d x^n\right )} \, dx &=\frac {(A b-a B) (e x)^{1+m}}{2 a (b c-a d) e n \left (a+b x^n\right )^2}-\frac {\int \frac {(e x)^m \left (-a B c (1+m)+A b c (1+m-2 n)+2 a A d n+(A b-a B) d (1+m-2 n) x^n\right )}{\left (a+b x^n\right )^2 \left (c+d x^n\right )} \, dx}{2 a (b c-a d) n}\\ &=\frac {(A b-a B) (e x)^{1+m}}{2 a (b c-a d) e n \left (a+b x^n\right )^2}+\frac {(A b (a d (1+m-4 n)-b c (1+m-2 n))+a B (b c (1+m)-a d (1+m-2 n))) (e x)^{1+m}}{2 a^2 (b c-a d)^2 e n^2 \left (a+b x^n\right )}+\frac {\int \frac {(e x)^m \left (-c (1+m) (A b (a d (1+m-4 n)-b c (1+m-2 n))+a B (b c (1+m)-a d (1+m-2 n)))+(b c-a d) n (a B c (1+m)-A b c (1+m-2 n)-2 a A d n)-d (A b (a d (1+m-4 n)-b c (1+m-2 n))+a B (b c (1+m)-a d (1+m-2 n))) (1+m-n) x^n\right )}{\left (a+b x^n\right ) \left (c+d x^n\right )} \, dx}{2 a^2 (b c-a d)^2 n^2}\\ &=\frac {(A b-a B) (e x)^{1+m}}{2 a (b c-a d) e n \left (a+b x^n\right )^2}+\frac {(A b (a d (1+m-4 n)-b c (1+m-2 n))+a B (b c (1+m)-a d (1+m-2 n))) (e x)^{1+m}}{2 a^2 (b c-a d)^2 e n^2 \left (a+b x^n\right )}+\frac {\int \left (\frac {\left (a B \left (2 a b c d (1+m) (1+m-2 n)-b^2 c^2 (1+m) (1+m-n)-a^2 d^2 \left (1+m^2+m (2-3 n)-3 n+2 n^2\right )\right )+A b \left (b^2 c^2 \left (1+m^2+m (2-3 n)-3 n+2 n^2\right )-2 a b c d \left (1+m^2+m (2-4 n)-4 n+3 n^2\right )+a^2 d^2 \left (1+m^2+m (2-5 n)-5 n+6 n^2\right )\right )\right ) (e x)^m}{(b c-a d) \left (a+b x^n\right )}+\frac {2 a^2 d^2 (-B c+A d) n^2 (e x)^m}{(-b c+a d) \left (c+d x^n\right )}\right ) \, dx}{2 a^2 (b c-a d)^2 n^2}\\ &=\frac {(A b-a B) (e x)^{1+m}}{2 a (b c-a d) e n \left (a+b x^n\right )^2}+\frac {(A b (a d (1+m-4 n)-b c (1+m-2 n))+a B (b c (1+m)-a d (1+m-2 n))) (e x)^{1+m}}{2 a^2 (b c-a d)^2 e n^2 \left (a+b x^n\right )}+\frac {\left (d^2 (B c-A d)\right ) \int \frac {(e x)^m}{c+d x^n} \, dx}{(b c-a d)^3}+\frac {\left (a B \left (2 a b c d (1+m) (1+m-2 n)-b^2 c^2 (1+m) (1+m-n)-a^2 d^2 \left (1+m^2+m (2-3 n)-3 n+2 n^2\right )\right )+A b \left (b^2 c^2 \left (1+m^2+m (2-3 n)-3 n+2 n^2\right )-2 a b c d \left (1+m^2+m (2-4 n)-4 n+3 n^2\right )+a^2 d^2 \left (1+m^2+m (2-5 n)-5 n+6 n^2\right )\right )\right ) \int \frac {(e x)^m}{a+b x^n} \, dx}{2 a^2 (b c-a d)^3 n^2}\\ &=\frac {(A b-a B) (e x)^{1+m}}{2 a (b c-a d) e n \left (a+b x^n\right )^2}+\frac {(A b (a d (1+m-4 n)-b c (1+m-2 n))+a B (b c (1+m)-a d (1+m-2 n))) (e x)^{1+m}}{2 a^2 (b c-a d)^2 e n^2 \left (a+b x^n\right )}+\frac {\left (a B \left (2 a b c d (1+m) (1+m-2 n)-b^2 c^2 (1+m) (1+m-n)-a^2 d^2 \left (1+m^2+m (2-3 n)-3 n+2 n^2\right )\right )+A b \left (b^2 c^2 \left (1+m^2+m (2-3 n)-3 n+2 n^2\right )-2 a b c d \left (1+m^2+m (2-4 n)-4 n+3 n^2\right )+a^2 d^2 \left (1+m^2+m (2-5 n)-5 n+6 n^2\right )\right )\right ) (e x)^{1+m} \, _2F_1\left (1,\frac {1+m}{n};\frac {1+m+n}{n};-\frac {b x^n}{a}\right )}{2 a^3 (b c-a d)^3 e (1+m) n^2}+\frac {d^2 (B c-A d) (e x)^{1+m} \, _2F_1\left (1,\frac {1+m}{n};\frac {1+m+n}{n};-\frac {d x^n}{c}\right )}{c (b c-a d)^3 e (1+m)}\\ \end {align*}
________________________________________________________________________________________
Mathematica [A] time = 0.34, size = 199, normalized size = 0.49 \[ \frac {x (e x)^m \left (\frac {(A b-a B) (b c-a d)^2 \, _2F_1\left (3,\frac {m+1}{n};\frac {m+n+1}{n};-\frac {b x^n}{a}\right )}{a^3}+\frac {b (b c-a d) (B c-A d) \, _2F_1\left (2,\frac {m+1}{n};\frac {m+n+1}{n};-\frac {b x^n}{a}\right )}{a^2}+\frac {b d (A d-B c) \, _2F_1\left (1,\frac {m+1}{n};\frac {m+n+1}{n};-\frac {b x^n}{a}\right )}{a}+\frac {d^2 (B c-A d) \, _2F_1\left (1,\frac {m+1}{n};\frac {m+n+1}{n};-\frac {d x^n}{c}\right )}{c}\right )}{(m+1) (b c-a d)^3} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
fricas [F] time = 0.94, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {{\left (B x^{n} + A\right )} \left (e x\right )^{m}}{b^{3} d x^{4 \, n} + a^{3} c + {\left (b^{3} c + 3 \, a b^{2} d\right )} x^{3 \, n} + 3 \, {\left (a b^{2} c + a^{2} b d\right )} x^{2 \, n} + {\left (3 \, a^{2} b c + a^{3} d\right )} x^{n}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (B x^{n} + A\right )} \left (e x\right )^{m}}{{\left (b x^{n} + a\right )}^{3} {\left (d x^{n} + c\right )}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
maple [F] time = 1.02, size = 0, normalized size = 0.00 \[ \int \frac {\left (B \,x^{n}+A \right ) \left (e x \right )^{m}}{\left (b \,x^{n}+a \right )^{3} \left (d \,x^{n}+c \right )}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ -{\left ({\left ({\left (m^{2} - m {\left (3 \, n - 2\right )} + 2 \, n^{2} - 3 \, n + 1\right )} b^{3} c^{2} e^{m} - 2 \, {\left (m^{2} - 2 \, m {\left (2 \, n - 1\right )} + 3 \, n^{2} - 4 \, n + 1\right )} a b^{2} c d e^{m} + {\left (m^{2} - m {\left (5 \, n - 2\right )} + 6 \, n^{2} - 5 \, n + 1\right )} a^{2} b d^{2} e^{m}\right )} A - {\left ({\left (m^{2} - m {\left (n - 2\right )} - n + 1\right )} a b^{2} c^{2} e^{m} - 2 \, {\left (m^{2} - 2 \, m {\left (n - 1\right )} - 2 \, n + 1\right )} a^{2} b c d e^{m} + {\left (m^{2} - m {\left (3 \, n - 2\right )} + 2 \, n^{2} - 3 \, n + 1\right )} a^{3} d^{2} e^{m}\right )} B\right )} \int -\frac {x^{m}}{2 \, {\left (a^{3} b^{3} c^{3} n^{2} - 3 \, a^{4} b^{2} c^{2} d n^{2} + 3 \, a^{5} b c d^{2} n^{2} - a^{6} d^{3} n^{2} + {\left (a^{2} b^{4} c^{3} n^{2} - 3 \, a^{3} b^{3} c^{2} d n^{2} + 3 \, a^{4} b^{2} c d^{2} n^{2} - a^{5} b d^{3} n^{2}\right )} x^{n}\right )}}\,{d x} - {\left (B c d^{2} e^{m} - A d^{3} e^{m}\right )} \int -\frac {x^{m}}{b^{3} c^{4} - 3 \, a b^{2} c^{3} d + 3 \, a^{2} b c^{2} d^{2} - a^{3} c d^{3} + {\left (b^{3} c^{3} d - 3 \, a b^{2} c^{2} d^{2} + 3 \, a^{2} b c d^{3} - a^{3} d^{4}\right )} x^{n}}\,{d x} - \frac {{\left ({\left (a b^{2} c e^{m} {\left (m - 3 \, n + 1\right )} - a^{2} b d e^{m} {\left (m - 5 \, n + 1\right )}\right )} A - {\left (a^{2} b c e^{m} {\left (m - n + 1\right )} - a^{3} d e^{m} {\left (m - 3 \, n + 1\right )}\right )} B\right )} x x^{m} + {\left ({\left (b^{3} c e^{m} {\left (m - 2 \, n + 1\right )} - a b^{2} d e^{m} {\left (m - 4 \, n + 1\right )}\right )} A + {\left (a^{2} b d e^{m} {\left (m - 2 \, n + 1\right )} - a b^{2} c e^{m} {\left (m + 1\right )}\right )} B\right )} x e^{\left (m \log \relax (x) + n \log \relax (x)\right )}}{2 \, {\left (a^{4} b^{2} c^{2} n^{2} - 2 \, a^{5} b c d n^{2} + a^{6} d^{2} n^{2} + {\left (a^{2} b^{4} c^{2} n^{2} - 2 \, a^{3} b^{3} c d n^{2} + a^{4} b^{2} d^{2} n^{2}\right )} x^{2 \, n} + 2 \, {\left (a^{3} b^{3} c^{2} n^{2} - 2 \, a^{4} b^{2} c d n^{2} + a^{5} b d^{2} n^{2}\right )} x^{n}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\left (e\,x\right )}^m\,\left (A+B\,x^n\right )}{{\left (a+b\,x^n\right )}^3\,\left (c+d\,x^n\right )} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
sympy [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: HeuristicGCDFailed} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________